如何使用StackMob作为后端获取sm_owner用户对象

我发现用户有一个sm_owner字段。 但是，如何让用户使用sm_owner。 我的代码是这样的：

[self.client getLoggedInUserOnSuccess:^(NSDictionary *result) { NSString *currentLogginedUser = [result valueForKey:@"sm_owner"]; NSFetchRequest *request = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"User" inManagedObjectContext:self.managedOjbectContext]; [request setEntity:entity]; NSPredicate *predicate = [NSPredicate predicateWithFormat:@"sm_owner like user/%@", currentLogginedUser]; [request setPredicate:predicate]; self.user = [[self.managedOjbectContext executeFetchRequest:request error:nil] objectAtIndex:0]; } onFailure:^(NSError *error) { }]; 

崩溃消息是：reason：'未实现的谓词的SQL生成（sm_owner LIKE user /“user / test”）'

Answer 1

我是StackMob的平台推广者。

getLoggedInUserOnSuccess方法的结果通常包含主键“username”。 所以下面的代码应该工作。

 [self.client getLoggedInUserOnSuccess:^(NSDictionary *result) { NSString *currentLogginedUser = [result objectForKey:@"username"]; NSFetchRequest *request = [[NSFetchRequest alloc] init]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"User" inManagedObjectContext:self.managedOjbectContext]; [request setEntity:entity]; NSPredicate *predicate = [NSPredicate predicateWithFormat:@"username == %@", currentLogginedUser]; [request setPredicate:predicate]; self.user = [[self.managedOjbectContext executeFetchRequest:request error:nil] objectAtIndex:0]; } onFailure:^(NSError *error) { }]; 

或者，如果你想从NSDictionary结果中获取sm_owner。 我会做以下。

 NSString *sm_owner = [result valueForKey:@"sm_owner"]; NSArray *myArray = [sm_owner componentsSeparatedByString:@"/"]; NSString *currentLogginedUser = [myArray objectAtIndex:1]; 

然后执行你的获取。