如何删除具有相同的属性值，但在NSMutableArray中的一个对象
我有一个URLstring属性和标题的历史对象。 我想search包含searchstring的url的所有历史logging，然后删除所有重复项。
例如：我有一组历史对象，其中20个都是“ https://www.google.com ”，4个是“ https://www.google.com/#q=search ”，我想要只有一个对象的url值为“ https://www.google.com ”，一个url值为“ https://www.google.com/#q=search ”的数组返回
这是我当前的代码，它search历史logging并返回匹配string的所有对象：
- (NSArray *)historyObjectsContainingQuery:(NSString *)query { NSMutableArray *matchingObjects = [[NSMutableArray alloc] init]; HistoryManager *HM = [HistoryManager sharedInstance]; for (int i=0; i<[[HM history] count]; i++) { //History "days" HistoryObject *historyItem = HistoryObject([[HistoryManager sharedInstance] history][i]); for (int o=0; o<[historyItem.objects count]; o++) { //Each object inn each history day HistoryObject *HO = HistoryObject(historyItem.objects[o]); if ([HO.title rangeOfString:query options:NSCaseInsensitiveSearch].location != NSNotFound) { //history objects with their title containing the query string [matchingObjects addObject:HO]; } } } return matchingObjects; } 然后我logging每个url值：
self.foundInBookmarksAndHistory = [self historyObjectsContainingQuery：textField.text]; （HistoryObject * HO in self.foundInBookmarksAndHistory）{NSLog（@“％@”，HO.url）; }
这里是结果：
https://www.google.com/ 2013-09-15 13:48:49.382 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.384 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.385 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.387 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.388 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.390 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.391 Flow HD[3599:60b] https://www.google.com/search?q=yahoo 2013-09-15 13:48:49.392 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.394 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.395 Flow HD[3599:60b] https://www.google.com/search?q=Sup 2013-09-15 13:48:49.397 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.398 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.400 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.402 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.404 Flow HD[3599:60b] https://www.google.com/ 2013-09-15 13:48:49.405 Flow HD[3599:60b] https://www.google.com/
还有很多，我怎么能删除每个对象具有相同的值？ 对象不相等，但是具有相同的URL。
我试过NSPredicate并使用更多的循环来通过并find匹配的对象，但即时通讯总是留下与2个或更多相同的对象具有相同的属性。
你可以做这样的事情：
NSMutableSet *seenObjects = [NSMutableSet set]; NSPredicate *dupPred = [NSPredicate predicateWithBlock: ^BOOL(id obj, NSDictionary *bind) { HistoryObject *hObj = (HistoryObject*)obj; BOOL seen = [seenObjects containsObject:hObj.title]; if (!seen) { [seenObjects addObject:hObj.title]; } return !seen; }]; NSArray *yourHistoryArray = ... // This is your array which needs to be filtered NSArray *yourHistoryArray = [yourHistoryArray filteredArrayUsingPredicate:dupObjectsPred];
我不确定这是search所有对象的最佳方法，但除了我能想到的最简单的修复方法是replace
if ([HO.title rangeOfString:query options:NSCaseInsensitiveSearch].location != NSNotFound) { [matchingObjects addObject:HO]; }
有了这个：
if ([HO.title rangeOfString:query options:NSCaseInsensitiveSearch].location != NSNotFound) { HistoryObject *temp = HistoryObject(historyItem.objects[o]); [historyItem.objects removeObjectAtIndex:o]; } //And after all the `for` loops [historyItem.objects addObject:temp];
您删除了所有匹配的对象，并将其添加到数组中一次。
编辑：阅读你的编辑后，使用isEqualToString而不是rangeOfString 。 rangeOfString会在abcd，abce和abcf中find单词abc，这不是你想要的。 abc的isEqualToString只对abc有效，没有别的。
如果对象仍然存在，则循环可变数组（如果需要，将数组更改为mutable）
while ([farray containsObject:_data]){ [farray removeObject:_data]; }