使用ASIFormDataRequest发送json到php

我是iPhone新手，我试图将NSMutable数组转换为jsonstring，然后使用请求将此string发送到php文件，然后使用响应NSLog再次打印，以确保它已成功发送。 所以我在viewDidLoad中编写了下面的代码

NSString *phpUrl = @"http://dt-works.com/eman/bookMarks.php"; NSMutableArray *arrayKey = [[NSMutableArray alloc] initWithObjects:@"one", @"two", @"three", nil]; NSMutableArray *arrayValue1 = [[NSMutableArray alloc] initWithObjects:@"1", @"2", @"3", nil]; NSMutableArray *arrayValue2 = [[NSMutableArray alloc] initWithObjects:@"11", @"22", @"33", nil]; NSDictionary *theReqDictionary1 = [NSDictionary dictionaryWithObjects:arrayValue1 forKeys:arrayKey]; NSDictionary *theReqDictionary2 = [NSDictionary dictionaryWithObjects:arrayValue2 forKeys:arrayKey]; NSMutableArray *myArray = [NSMutableArray arrayWithObjects:theReqDictionary1,theReqDictionary2, nil]; NSString *jsonString = [myArray JSONRepresentation]; NSLog(@"%@", jsonString); NSDictionary *questions = nil; NSURL *link = [NSURL URLWithString:[phpUrl stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]; ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:link]; [request setPostValue:jsonString forKey:@"jsonString"]; [request setTimeOutSeconds:120]; [request setDelegate:self]; NSError *error = [request2 error]; [request2 startSynchronous]; if (!error) { NSData *response = [request responseData]; NSString *json = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]; questions = [json objectFromJSONString]; NSLog(@"Data: %@", questions); } 

而bookMarks.php中的代码是：

 $handle = fopen('php://input','r'); $jsonInput = $_POST['jsonString']; print_r($jsonInput); 

但它给了我：

 [{"one":"1","two":"2","three":"3"},{"one":"11","two":"22","three":"33"}] Data: (null) 

我希望数据为：[{“一”：“1”，“two”：“2”，“three”：“3”}，{“one”：“11”，“two”：“22 “，”三“：”33“}]如何做到这一点？

Answer 1

试试这个，而不是用一个键发布JSONstring，你需要把它作为数据发布到你的脚本中读取。目前在你的脚本中，甚至没有使用$ handle来处理任何事情…

 NSURL *link = [NSURL URLWithString:[phpUrl stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]; ASIFormDataRequest *request = [ASIFormDataRequest requestWithURL:link]; [request appendPostData:[jsonString dataUsingEncoding:NSUTF8StringEncoding]]; [request setTimeOutSeconds:120]; [request setDelegate:self]; 

和你的PHP代码..

 $handle = fopen('php://input','r'); $jsonInput = fgets($handle); $decoded = json_decode($jsonInput,true); print_r($decoded);