Alamofire：完成错误 – 代码：-1001

像这样的代码：

import Foundation import Alamofire struct Request { var alamoFireManager : SessionManager? init() { let configuration = URLSessionConfiguration.default configuration.timeoutIntervalForRequest = 20 configuration.requestCachePolicy = .useProtocolCachePolicy alamoFireManager = Alamofire.SessionManager(configuration: configuration) } func sendRequest() { alamoFireManager?.request(url,method: method, parameters: body, encoding: JSONEncoding.default,headers: headers).responseJSON { response in } } } 

Answer 1

我已经完成了这项工作（快速4代码）。

 import UIKit import Alamofire class SplashViewController: UIViewController { var alamoFireManager = Alamofire.SessionManager.default override func viewDidLoad() { super.viewDidLoad() self.callPostApi() } func callPostApi() { let configuration = URLSessionConfiguration.default configuration.timeoutIntervalForRequest = 20 // seconds configuration.timeoutIntervalForResource = 20 configuration.requestCachePolicy = .useProtocolCachePolicy alamoFireManager = Alamofire.SessionManager(configuration: configuration) alamoFireManager.request(url, method: .post, parameters: ["jsondata":base64EncodedString]) .responseJSON { response in switch (response.result) { case .success: print(response.data as? Data) if let json = response.result.value { print("JSON: \(json)") // Here is your JSON Response } //do json stuff case .failure(let error): if error._code == NSURLErrorTimedOut || error._code == -1005{ //HANDLE TIMEOUT HERE print("TimeOut") } print("\n\nAuth request failed with error:\n \(error)") break } } } } 

Answer 2

SessionManager不能正常使用我。 最好在Alamofire中使用这样的代码：

 let request = URLRequest(url: url) request.httpMethod = "GET" //Some configuration Alamofire.request(request).responseJSON { response in } 

Answer 3

这是一个超时错误。 如果可能，只需增加超时值，或提高API的性能。