Xmpp IOS多用户聊天。 我没有找到接受小组邀请的方法？ 我怎么能接受这个邀请函

当我发送邀请时，这个function被调用，但我无法理解接受邀请*应使用哪一行代码 。 我正在尝试创建一个多用户和多组邀请，也称为已接收消息function。

- (void)xmppMUC:(XMPPMUC *) sender roomJID:(XMPPJID *) roomJID didReceiveInvitation:(XMPPMessage *)message { } 

Answer 1

这是您接受群组邀请的方式。 您只需要激活您的XMPPMUC协议，如下所示：

 XMPPMUC * xmppMUC = [[XMPPMUC alloc] initWithDispatchQueue:dispatch_get_main_queue()]; [xmppMUC activate:_xmppStream]; [xmppMUC addDelegate:self delegateQueue:dispatch_get_main_queue()]; 

接受MUC的传入邀请：

 - (void)xmppMUC:(XMPPMUC *)sender didReceiveRoomInvitation:(XMPPMessage *)message { NSXMLElement * x = [message elementForName:@"x" xmlns:XMPPMUCUserNamespace]; NSXMLElement * invite = [x elementForName:@"invite"]; if (!isEmpty(invite)) { NSString * conferenceRoomJID = [[message attributeForName:@"from"] stringValue]; [self joinMultiUserChatRoom:conferenceRoomJID]; } } - (void) joinMultiUserChatRoom:(NSString *) newRoomName { XMPPJID *roomJID = [XMPPJID jidWithString:newRoomName]; XMPPRoomMemoryStorage *roomMemoryStorage = [[XMPPRoomMemoryStorage alloc] init]; xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:roomMemoryStorage jid:roomJID dispatchQueue:dispatch_get_main_queue()]; [xmppRoom activate:[self xmppStream]]; [xmppRoom addDelegate:self delegateQueue:dispatch_get_main_queue()]; [xmppRoom joinRoomUsingNickname:@"YOUR NICKNAME" history:nil]; } 

Answer 2

接受来电邀请：

 - (void)xmppMUC:(XMPPMUC *)sender roomJID:(XMPPJID *) roomJID didReceiveInvitation:(XMPPMessage *)message { XMPPRoom *mu = [[XMPPRoom alloc] initWithRoomStorage:xmpproomMstorage jid:roomJID dispatchQueue:dispatch_get_main_queue()]; [mu activate:xmppStream]; [mu addDelegate:self delegateQueue:dispatch_get_main_queue()]; self.toSomeOne = roomJID; [mu activate: self.xmppStream]; [mu fetchConfigurationForm]; [mu addDelegate:self delegateQueue:dispatch_get_main_queue()]; [mu joinRoomUsingNickname:xmppStream.YourJid.user history:nil password:@"Your Password"]; self.toSomeOne = roomJID; XMPPPresence *presence = [XMPPPresence presence]; [[self xmppStream] sendElement:presence]; [xmppRoster addUser:roomJID withNickname:roomJID.full]; [self goOnline]; } 

Answer 3

在我的情况下，我需要使用两个答案并定义自己喜欢

 @interface XMPPDelegate : NSObject  

激活XMPPMUC协议如下：

 XMPPMUC * xmppMUC = [[XMPPMUC alloc] initWithDispatchQueue:dispatch_get_main_queue()]; [xmppMUC activate:_xmppStream]; [xmppMUC addDelegate:self delegateQueue:dispatch_get_main_queue()]; 

收到加入消息：

 - (void)xmppMUC:(XMPPMUC *)sender roomJID:(XMPPJID *) roomJID didReceiveInvitation:(XMPPMessage *)message { DDLogDebug(@"%@", message); XMPPRoomMemoryStorage *roomMemoryStorage = [[XMPPRoomMemoryStorage alloc] init]; XMPPRoom *xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:roomMemoryStorage jid:roomJID dispatchQueue:dispatch_get_main_queue()]; [xmppRoom activate:xmppStream]; [xmppRoom addDelegate:self delegateQueue:dispatch_get_main_queue()]; [xmppRoom joinRoomUsingNickname: xmppStream.myJID.user history:nil password:password]; XMPPPresence *presence = [XMPPPresence presence]; [[self xmppStream] sendElement:presence]; [xmppRoster addUser:roomJID withNickname:roomJID.full]; [self goOnline]; }