如何用xml正文发送alamofire请求

我在我的项目中安装了Alamofire，现在我已经做了。

我安装了邮递员 ，我把我的url和体内一个XML对象，我得到了我的结果。

这是一张我刚刚和邮递员做过的照片

我现在如何使用Alamofire或SWXMLHash发送它，因为我发送邮递员

提前致谢！

编辑

我从另一个问题尝试了这个：

Alamofire.request(.POST, "https://something.com" , parameters: Dictionary(), encoding: .Custom({ (convertible, params) in let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest let data = (self.testString as NSString).dataUsingEncoding(NSUTF8StringEncoding) mutableRequest.HTTPBody = data return (mutableRequest, nil) })) .responseJSON { response in print(response.response) print(response.result) } } 

但它没有发送任何东西

这是日志：

可选（{URL： https ： //something.com } {status code：200，headers {Connection =“keep-alive”;“Content-Length”= 349;“Content-Type”=“application / xml” =“Wed，02 Nov 2016 21:13:32 GMT”; Server = nginx;“Strict-Transport-Security”=“max-age = 31536000; includeSubDomains”;}}）

失败

编辑

不要忘了通过参数，如果你没有简单的添加这个参数：Dictionary（）

Answer 1

假设您在请求中缺less有效的HTTP标头，则更新后的请求可能如下所示：

 Alamofire.request(.POST, "https://something.com", parameters: Dictionary() , encoding: .Custom({ (convertible, params) in let mutableRequest = convertible.URLRequest.copy() as! NSMutableURLRequest let data = (self.testString as NSString).dataUsingEncoding(NSUTF8StringEncoding) mutableRequest.HTTPBody = data mutableRequest.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type") return (mutableRequest, nil) })) .responseJSON { response in print(response.response) print(response.result) } } 

所以，基本上你应该添加一行

 mutableRequest.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type") 

更新 ：
尝试相同，但使用responseData或responseString而不是responseJSON因为您的响应可能不是JSON

Answer 2

用Swift 3和Alamofire 4你可以创build一个自定义的ParameterEncoding 。 与其他任何XML编码体一样，SOAP消息可以使用此参数编码，如下例所示。 其他的XML身体编码可以类似地创build（检查它所说的urlRequest.httpBody = ... ）：

 struct SOAPEncoding: ParameterEncoding { let service: String let action: String func encode(_ urlRequest: URLRequestConvertible, with parameters: Parameters?) throws -> URLRequest { var urlRequest = try urlRequest.asURLRequest() guard let parameters = parameters else { return urlRequest } if urlRequest.value(forHTTPHeaderField: "Content-Type") == nil { urlRequest.setValue("text/xml", forHTTPHeaderField: "Content-Type") } if urlRequest.value(forHTTPHeaderField: "SOAPACTION") == nil { urlRequest.setValue("\(service)#\(action)", forHTTPHeaderField: "SOAPACTION") } let soapArguments = parameters.map({key, value in "<\(key)>\(value)</\(key)>"}).joined(separator: "") let soapMessage = "<s:Envelope xmlns:s='http://schemas.xmlsoap.org/soap/envelope/' s:encodingStyle='http://schemas.xmlsoap.org/soap/encoding/'>" + "<s:Body>" + "<u:\(action) xmlns:u='\(service)'>" + soapArguments + "</u:\(action)>" + "</s:Body>" + "</s:Envelope>" urlRequest.httpBody = soapMessage.data(using: String.Encoding.utf8) return urlRequest } } 

然后像这样使用它：

 Alamofire.request(url, method: .post, parameters: ["parameter" : "value"], encoding: SOAPEncoding(service: "service", action: "action")) 

Answer 3

使用Swift 3和Alamofire 4

  let stringParams : String = "<msg id=\"123123\" reqTime=\"123123\">" + "<params class=\"API\">" + "<param name=\"param1\">123213</param>" + "<param name=\"param2\">1232131</param>" + "</params>" + "</msg>" let url = URL(string:"<#URL#>") var xmlRequest = URLRequest(url: url!) xmlRequest.httpBody = stringParams.data(using: String.Encoding.utf8, allowLossyConversion: true) xmlRequest.httpMethod = "POST" xmlRequest.addValue("application/xml", forHTTPHeaderField: "Content-Type") Alamofire.request(xmlRequest) .responseData { (response) in let stringResponse: String = String(data: response.data!, encoding: String.Encoding.utf8) as String! debugPrint(stringResponse) }