获取URL参数的值

我试图从一个URL使用swift的参数。 假设我有以下url：

http://mysite3994.com?test1=blah&test2=blahblah 

我怎样才能得到test1和test2的值？

Answer 1

你可以使用belowCode来获取参数

 func getQueryStringParameter(url: String, param: String) -> String? { guard let url = URLComponents(string: url) else { return nil } return url.queryItems?.first(where: { $0.name == param })?.value } 

调用像let test1 = getQueryStringParameter(url, param: "test1")

其他扩展方法：

 extension URL { public var queryParameters: [String: String]? { guard let components = URLComponents(url: self, resolvingAgainstBaseURL: true), let queryItems = components.queryItems else { return nil } var parameters = [String: String]() for item in queryItems { parameters[item.name] = item.value } return parameters } } 

Answer 2

第1步：创buildurl扩展程序：

  extension URL { func valueOf(queryParamaterName: String) -> String? { guard let url = URLComponents(string: self.absoluteString) else { return nil } return url.queryItems?.first(where: { $0.name == queryParamaterName })?.value } } 

步骤：2如何使用扩展名

  let newURL = URL(string: "http://mysite3994.com?test1=blah&test2=blahblah")! newURL.valueOf("test1") // Output ie "blah" newURL.valueOf("test2") // Output ie "blahblah" 

Answer 3

我也做了一个URL扩展，但把查询参数查找成一个下标。

 extension URL { subscript(queryParam:String) -> String? { guard let url = URLComponents(string: self.absoluteString) else { return nil } return url.queryItems?.first(where: { $0.name == queryParam })?.value } } 

用法：

 let url = URL(string: "http://some-website.com/documents/127/?referrer=147&mode=open")! let referrer = url["referrer"] // "147" let mode = url["mode"] // "open"