在特定的日子重复UILocalNotification

我需要设置UILocalNotification，我只需要从DatePicker中花费小时和分钟，并需要设置特定的date（如：星期一） ，并在每个星期一重复。

我有两个问题：

第一 ; 是否可以在dateselect器的date部分仅显示“星期天”这样的“date名称”？

第二个问题是， 如果我想为本地通知设置特定的date，那么正确的代码是什么？

谢谢你的答案，这里是我的代码如下; 

-(IBAction) alarmButton:(id)sender { NSDateFormatter *dateFormatter = [[NSDateFormatter alloc]init]; dateFormatter.timeZone = [NSTimeZone defaultTimeZone]; dateFormatter.timeStyle = NSDateFormatterShortStyle; dateFormatter.dateStyle = NSDateFormatterShortStyle; NSString *dateTimeString = [dateFormatter stringFromDate: dateTimePickerSet1.date]; NSLog ( @"Alarm Set :%@" , dateTimeString); [self scheduleLocalNotificationWithDate1: dateTimePickerSet1.date]; } -(void)scheduleLocalNotificationWithDate1:(NSDate *)fireDate { UILocalNotification *notification = [[UILocalNotification alloc] init]; notification.fireDate = fireDate; notification.alertBody = @"Alarm Set !"; [[UIApplication sharedApplication] scheduleLocalNotification:notification];

问题1 =>我不明白你想要什么。 （但是，如果你只想显示星期几，星期一，…星期六，然后使用UIPickerView。

问题2 => 是的，你可以得到正确的date的具体一天，你可以通过设置localNotification.repeatInterval = NSWeekCalendarUnit;

为了实现它，还需要使用下面的一段（方法）代码。 此方法将返回特定选定date的正确date，您只需将date作为方法的参数，

如果选定的日子是星期日，那么通过1
如果选定的一天是星期一，然后通过2
。
。
。
如果选定date是星期六，则通过7

这里是方法代码： 

 -(NSDate *) getDateOfSpecificDay:(NSInteger ) day /// here day will be 1 or 2.. or 7 { NSInteger desiredWeekday = day NSRange weekDateRange = [[NSCalendar currentCalendar] maximumRangeOfUnit:NSWeekdayCalendarUnit]; NSInteger daysInWeek = weekDateRange.length - weekDateRange.location + 1; NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit fromDate:[NSDate date]]; NSInteger currentWeekday = dateComponents.weekday; NSInteger differenceDays = (desiredWeekday - currentWeekday + daysInWeek) % daysInWeek; NSDateComponents *daysComponents = [[NSDateComponents alloc] init]; daysComponents.day = differenceDays; NSDate *resultDate = [[NSCalendar currentCalendar] dateByAddingComponents:daysComponents toDate:[NSDate date] options:0]; return resultDate; }

不要忘记设置localNotification.repeatInterval = NSWeekCalendarUnit;

这是@ iPatel的解决scheme，也是通过dateselect器传入的时间组件的因素。 （我还更新了他的解决scheme，以使用最新的日历单位，不被弃用）。 

 - (NSDate *) getFireDateForDayOfWeek:(NSInteger)desiredWeekday withTime:(NSDate *)time // 1:Sunday - 7:Saturday { NSRange weekDateRange = [[NSCalendar currentCalendar] maximumRangeOfUnit:NSCalendarUnitWeekday]; NSInteger daysInWeek = weekDateRange.length - weekDateRange.location + 1; NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSCalendarUnitWeekday fromDate:[NSDate date]]; NSInteger currentWeekday = dateComponents.weekday; NSInteger differenceDays = (desiredWeekday - currentWeekday + daysInWeek) % daysInWeek; NSDateComponents *daysComponents = [[NSDateComponents alloc] init]; daysComponents.day = differenceDays; NSDate *fireDate = [[NSCalendar currentCalendar] dateByAddingComponents:daysComponents toDate:[NSDate date] options:0]; NSDateComponents *timeComponents = [[NSCalendar currentCalendar] components: NSCalendarUnitHour | NSCalendarUnitMinute fromDate:time]; NSDateComponents *fireDateComponents = [[NSCalendar currentCalendar] components: NSCalendarUnitYear | NSCalendarUnitMonth | NSCalendarUnitDay | NSCalendarUnitHour | NSCalendarUnitMinute | NSCalendarUnitSecond fromDate:fireDate]; fireDateComponents.hour = timeComponents.hour; fireDateComponents.minute = timeComponents.minute; fireDateComponents.second = 0; NSDate *resultDate = [[NSCalendar currentCalendar] dateFromComponents:fireDateComponents]; // The day could be today but time is in past. If so, move ahead to next week if(resultDate.timeIntervalSinceNow < 0) { resultDate = [resultDate dateByAddingTimeInterval:60 * 60 * 24 * 7]; } return resultDate; }

这个解决scheme同样需要时间，但比Oren更简单一些 

 -(NSDate *) dateOfSpecificDay:(NSInteger ) day withFireTime:(NSDate *)timeDate/// here day will be 1 or 2.. or 7 and timeDate the current day with the desired time { NSInteger desiredWeekday = day; NSRange weekDateRange = [[NSCalendar currentCalendar] maximumRangeOfUnit:NSCalendarUnitWeekday]; NSInteger daysInWeek = weekDateRange.length - weekDateRange.location + 1; NSDateComponents *dateComponents = [[NSCalendar currentCalendar] components:NSCalendarUnitWeekday fromDate:[NSDate date]]; NSInteger currentWeekday = dateComponents.weekday; NSInteger differenceDays = (desiredWeekday - currentWeekday + daysInWeek) % daysInWeek; if (differenceDays == 0) { //Check if should register for same day or for next week if ([timeDate compare:[NSDate date]] == NSOrderedAscending) { //Should schedule for next week differenceDays = daysInWeek; } } NSDateComponents *daysComponents = [[NSDateComponents alloc] init]; daysComponents.day = differenceDays; NSDate *resultDate = [[NSCalendar currentCalendar] dateByAddingComponents:daysComponents toDate:timeDate options:0]; return resultDate; }

这里是迅捷版本： 

 func calculateTheNExtFriday(inputTime: NSDate) -> NSDate { let desiredWeekday = 6 // Friday let weekDateRange = NSCalendar.currentCalendar().maximumRangeOfUnit(NSCalendarUnit.Weekday) let daysInWeek = weekDateRange.length - weekDateRange.location + 1; let currentWeekday = NSCalendar.currentCalendar().components(NSCalendarUnit.Weekday, fromDate: inputTime).weekday let differenceDays = (desiredWeekday - currentWeekday + daysInWeek) % daysInWeek let dateComponents = NSDateComponents() dateComponents.day = differenceDays let calculatedFridayDate = NSCalendar.currentCalendar().dateByAddingComponents(dateComponents, toDate: inputTime, options: NSCalendarOptions.init(rawValue: 0)) return calculatedFridayDate! }

在这个例子中，我使用函数里面的desiredWeekday，但是也可以用它作为参数。

注意：请注意，第1天对应于星期日，2 – >星期一等

Swift 3： 

 func calculateSpecificDay(_ desiredWeekday: NSInteger, fromDate: Date = Date()) -> Date { let weekDateRange = NSCalendar.current.maximumRange(of: .weekday)! let daysInWeek = weekDateRange.lowerBound.distance(to: weekDateRange.upperBound) - weekDateRange.lowerBound + 1 let currentWeekday = NSCalendar.current.dateComponents([.weekday], from: fromDate).weekday let differenceDays = (desiredWeekday - currentWeekday! + daysInWeek) % daysInWeek var dateComponents = DateComponents() dateComponents.day = differenceDays let calculatedFridayDate = NSCalendar.current.date(byAdding: dateComponents, to: fromDate) return calculatedFridayDate! } 
 If selected day is sunday then pass 1 If selected day is monday then pass 2 . . . If selected day is saturday then pass 7
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