希望通过在swift中使用swipe gesters在标签栏之间导航

我想要使​​用滑动手势在标签栏控制器之间导航，同时保持默认的标签栏。 我用这个代码，但显示一个错误。

import UIKit class FirstViewController: UIViewController { override func viewDidLoad() { super.viewDidLoad() var leftSwipe = UISwipeGestureRecognizer(target: self, action: Selector("handleSwipes:")) leftSwipe.direction = .Left view.addGestureRecognizer(leftSwipe) } override func didReceiveMemoryWarning() { super.didReceiveMemoryWarning() // Dispose of any resources that can be recreated. func handleSwipes(sender:UISwipeGestureRecognizer) { if (sender.direction == .Left) { let storyboard = UIStoryboard(name: "Main", bundle: nil) let vc = storyboard.instantiateViewControllerWithIdentifier("SecondViewController") as! UIViewController self.presentViewController(vc, animated: false, completion: nil) } if (sender.direction == .Right) { } } } } 

Answer 1

你的函数handleSwipes必须是一个类级别的函数，而不是另一个函数的内部函数：

 override func didReceiveMemoryWarning() { super.didReceiveMemoryWarning() // Dispose of any resources that can be recreated. // remove the func from here } func handleSwipes(sender:UISwipeGestureRecognizer) { if (sender.direction == .Left) { let storyboard = UIStoryboard(name: "Main", bundle: nil) let vc = storyboard.instantiateViewControllerWithIdentifier("SecondViewController") as! UIViewController self.presentViewController(vc, animated: false, completion: nil) } if (sender.direction == .Right) { } } 

这是我可以看到的明显的错误。 你应该总是发布你的错误信息与你的问题，以提高答案的质量。

Answer 2

我可以通过将ID添加到SecondViewController类来获取代码，如下图所示：

唯一的问题是，得到这个工作后，你将无法看到Tab栏控制器，因为你打开了没有UI Tab栏控制器的SecondViewController。

请让我知道，如果我的解决scheme的工作原理，你有没有find其他方式刷到第二个视图，并具有UI标签栏。

[编辑]其实我挖了多一点，发现它比我想象的更容易。 我们对tabBar控制器问题的解决方法没有显示如下：

  func handleSwipes(sender:UISwipeGestureRecognizer) { let selectedIndex: Int = self.tabBarController!.selectedIndex self.tabBarController!.selectedIndex = selectedIndex + 1 } 

Answer 3

接下来是UITabBarViewController（Swift 3.0）的最佳方式：

func handleSwipes（发件人：UISwipeGestureRecognizer）{

  if sender.direction == UISwipeGestureRecognizerDirection.left { self.selectedIndex += 1 } else if sender.direction == UISwipeGestureRecognizerDirection.right { self.selectedIndex -= 1 } } 

Answer 4

你应该使用UITabBarControllerDelegate方法来完成这个。 UITabBarControllerDelegate上有新的委托方法，可以让你返回UIViewControllerAnimatedTransitioning和UIViewControllerInteractiveTransitioning 。

这些是您将使用的委托方法，

 - (id <UIViewControllerInteractiveTransitioning>)tabBarController:(UITabBarController *)tabBarController interactionControllerForAnimationController: (id <UIViewControllerAnimatedTransitioning>)animationController; - (id <UIViewControllerAnimatedTransitioning>)tabBarController:(UITabBarController *)tabBarController animationControllerForTransitionFromViewController:(UIViewController *)fromVC toViewController:(UIViewController *)toVC; 

代表方法的Swift代码看起来像这样，

 func tabBarController(tabBarController: UITabBarController, interactionControllerForAnimationController animationController: UIViewControllerAnimatedTransitioning) -> UIViewControllerInteractiveTransitioning? func tabBarController(tabBarController: UITabBarController, animationControllerForTransitionFromViewController fromVC: UIViewController, toViewController toVC: UIViewController) -> UIViewControllerAnimatedTransitioning? 

Answer 5

复制广告粘贴这个

 class SwipeGesture: UIViewController { override func viewDidLoad() { super.viewDidLoad() let left = UISwipeGestureRecognizer(target: self, action: #selector(swipeLeft)) left.direction = .left self.view.addGestureRecognizer(left) let right = UISwipeGestureRecognizer(target: self, action: #selector(swipeRight)) right.direction = .right self.view.addGestureRecognizer(right) } @objc func swipeLeft() { let total = self.tabBarController!.viewControllers!.count - 1 tabBarController!.selectedIndex = min(total, tabBarController!.selectedIndex + 1) } @objc func swipeRight() { tabBarController!.selectedIndex = max(0, tabBarController!.selectedIndex - 1) } }