SQLite iOS插入数据

我试图插入一个名字到我的sqlite文件。 即时通讯使用此代码，但它不工作：/

-(void)InsertRecords:(NSMutableString *) txt{ if(addStmt == nil) { const char *sql = "INSERT INTO myMovies (movieName) VALUES(?) "; if(sqlite3_prepare_v2(database, sql, -1, &addStmt, NULL) != SQLITE_OK) NSAssert1(0, @"Error while creating add statement. '%s'", sqlite3_errmsg(database)); else sqlite3_bind_text(addStmt, 1, [txt UTF8String], -1, SQLITE_TRANSIENT); } if(SQLITE_DONE != sqlite3_step(addStmt)) NSAssert1(0, @"Error while inserting data. '%s'", sqlite3_errmsg(database)); else sqlite3_reset(addStmt); } 

Answer 1

传递你的查询到这个方法并尝试，

 -(void)Insertdata:(NSString*)query{ NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES); NSString *documentsDirectory = [paths objectAtIndex:0]; NSString *databasePath = [documentsDirectory stringByAppendingPathComponent:@"YourDBName.sql"]; if(sqlite3_open([databasePath UTF8String],&db) == SQLITE_OK) { NSString *querySQL = [NSString stringWithFormat: @"%@",query]; char *errmsg=nil; if(sqlite3_exec(db, [querySQL UTF8String], NULL, NULL, &errmsg)==SQLITE_OK) { NSLog(@".. Row Added .."); } } sqlite3_close(db); } 

Answer 2

来自sqlite的“内存不足”错误通常意味着您正在使用的数据库句柄尚未打开。 确保你使用你发布的代码中显示的databasevariables调用sqlite3_open_v2 ？

Answer 3

好吧，我终于做到了！ 这是我用于每个需要它的人的代码：

 -(void)InsertRecords:(NSMutableString *)txt{ NSString *dbPath = [[[NSBundle mainBundle] resourcePath ]stringByAppendingPathComponent:@"movieData.sqlite"]; const char *dbpath = [dbPath UTF8String]; sqlite3 *contactDB; sqlite3_stmt *statement; NSLog(@"%@",dbPath); if (sqlite3_open(dbpath, &contactDB) == SQLITE_OK) { NSString *insertSQL = [NSString stringWithFormat: @"INSERT INTO myMovies (movieName) VALUES (\"%@\")", txt]; const char *insert_stmt = [insertSQL UTF8String]; sqlite3_prepare_v2(contactDB, insert_stmt, -1, &statement, NULL); if (sqlite3_step(statement) == SQLITE_DONE) { sqlite3_bind_text(statement, 1, [txt UTF8String], -1, SQLITE_TRANSIENT); } else { NSLog(@"error"); } sqlite3_finalize(statement); sqlite3_close(contactDB); } } 

Answer 4

尝试这个：

 //save our data - (BOOL) saveEmployee:(Employee *)employee { BOOL success = false; sqlite3_stmt *statement = NULL; const char *dbpath = [databasePath UTF8String]; if (sqlite3_open(dbpath, &mySqliteDB) == SQLITE_OK) { if (employee.employeeID > 0) { NSLog(@"Exitsing data, Update Please"); NSString *updateSQL = [NSString stringWithFormat:@"UPDATE EMPLOYEES set name = '%@', department = '%@', age = '%@' WHERE id = ?", employee.name, employee.department, [NSString stringWithFormat:@"%d", employee.age]]; const char *update_stmt = [updateSQL UTF8String]; sqlite3_prepare_v2(mySqliteDB, update_stmt, -1, &statement, NULL ); sqlite3_bind_int(statement, 1, employee.employeeID); if (sqlite3_step(statement) == SQLITE_DONE) { success = true; } } else{ NSLog(@"New data, Insert Please"); NSString *insertSQL = [NSString stringWithFormat: @"INSERT INTO EMPLOYEES (name, department, age) VALUES (\"%@\", \"%@\", \"%@\")", employee.name, employee.department, [NSString stringWithFormat:@"%d", employee.age]]; const char *insert_stmt = [insertSQL UTF8String]; sqlite3_prepare_v2(mySqliteDB, insert_stmt, -1, &statement, NULL); if (sqlite3_step(statement) == SQLITE_DONE) { success = true; } } sqlite3_finalize(statement); sqlite3_close(mySqliteDB); } return success; }