基于NSString序列的字输出

我想要做的是从NSString中取3个字母的单词序列，并将其更改为相应的单词。 EX）AUG =“START”，AGC =“天冬酰胺”等等。我的想法是把NSString改成一个NSArray，每个元素包含3个字母，然后我可以在for循环中引用它们来创build一个新的string与导致的话。

例：

NSDictionary *aminoReplaceDict = @{ @"AAA" : @"Lysine", @"AAC" : @"Asparagine", @"AAG" : @"Lysine", @"AAU" : @"Asparagine", @"ACA" : @"Threonine", @"ACC" : @"Threonine", @"ACG" : @"Threonine", @"ACU" : @"Threonine", @"AGA" : @"Arginine", @"AGC" : @"Serine", @"AGG" : @"Arginine", @"AGU" : @"Serine", @"AUA" : @"Isoleucine", @"AUC" : @"Isoleucine", @"AUG" : @"START", @"AUU" : @"Isoleucine", @"CAA" : @"Glutamine", @"CAC" : @"Histidine", @"CAG" : @"Glutamine", @"CAU" : @"Histidine", @"CCA" : @"Proline", @"CCC" : @"Proline", @"CCG" : @"Proline", @"CCU" : @"Proline", @"CGA" : @"Arginine", @"CGC" : @"Arginine", @"CGG" : @"Arginine", @"CGU" : @"Arginine", @"CUA" : @"Leucine", @"CUC" : @"Leucine", @"CUG" : @"Leucine", @"CUU" : @"Leucine", @"GAA" : @"Glutamic Acid", @"GAC" : @"Aspartic Acid", @"GAG" : @"Glutamic Acid", @"GAU" : @"Aspartic Acid", @"GCA" : @"Alanine", @"GCC" : @"Alanine", @"GCG" : @"Alanine", @"GCU" : @"Alanine", @"GGA" : @"Glycine", @"GGC" : @"Glycine", @"GGG" : @"Glycine", @"GGU" : @"Glycine", @"GUA" : @"Valine", @"GUC" : @"Valine", @"GUG" : @"Valine", @"GUU" : @"Valine", @"UAA" : @"STOP", @"UAC" : @"Tyrosine", @"UAG" : @"STOP", @"UAU" : @"Tyrosine", @"UCA" : @"Serine", @"UCC" : @"Serine", @"UCG" : @"Serine", @"UCU" : @"Serine", @"UGA" : @"STOP", @"UGC" : @"Cysteine", @"UGG" : @"Tryptonphan", @"UGU" : @"Cysteine", @"UUA" : @"Leucine", @"UUC" : @"Phenylalanine", @"UUG" : @"START", @"UUU" : @"Phenylalanine", }; NSMutableString *replaceString = [NSMutableString stringWithString:_trnaOut.text]; for( NSString *replaceWord in [aminoReplaceDict allKeys] ) { [replaceString replaceOccurrencesOfString:replaceWord withString:aminoReplaceDict[replaceWord] options:NSCaseInsensitiveSearch range:NSMakeRange(0, replaceString.length )]; } _aminoOut.text = replaceString; 

输出：

Answer 1

这应该工作（遗漏在你的问题是相同的字典）：

  NSString *exampleString = @"AAACAACAU"; NSMutableArray *stringArray = [[NSMutableArray alloc] init]; for( int i = 0; i < exampleString.length; i += 3) { NSString *substring = [exampleString substringWithRange:NSMakeRange(i, 3)]; [stringArray addObject:substring]; } NSMutableArray *replacedArray = [[NSMutableArray alloc] init]; for( NSString *key in stringArray) { NSString *replacedWord = aminoReplaceDict[key]; [replacedArray addObject:replacedWord]; } NSString *replaceString = [replacedArray componentsJoinedByString:@", "]; NSLog(@"%@", replaceString); 

Answer 2

@riley Lloyd，据我了解你的要求如下： –

 First you need to split your string into three characters:- NSString *yourString = @"AUCGUAUCA"; //it will give you AUC NSRange oneToThreeRange= NSMakeRange(0, 3); NSString *oneToThree= [yourString substringWithRange:oneToThreeRange]; //it will give you GUA NSRange fourToSixRange= NSMakeRange(3, 3); NSString *fourToSix= [yourString substringWithRange:fourToSixRange]; //it will give you UCA NSRange sixToNineRange= NSMakeRange(6, 3); NSString *sixToNine= [yourString substringWithRange:sixToNineRange]; //Now add on your array and perform what you want to do NSArray * youArr=[NSArray arrayWithObjects:oneToThree,fourToSix,sixToNine,nil]; NSLog(@"%@",youArr);