NSPredicate从PHFetchResults中排除慢动作video

NSString *predicateFormat = [NSString stringWithFormat: @"mediaSubtype = %zd", PHAssetMediaSubtypeVideoHighFrameRate]; NSPredicate *predicate = [NSPredicate predicateWithFormat: predicateFormat]; PHFetchOptions *fetchOptions = [PHFetchOptions new]; fetchOptions.predicate = predicate; PHFetchResult *userAlbums = [PHAssetCollection fetchAssetCollectionsWithType:PHAssetCollectionTypeSmartAlbum subtype:PHAssetCollectionSubtypeSmartAlbumVideos options:fetchOptions]; 

这是我的代码，以获取排除慢动作video的video。 但是我得到下面的错误。即使我这样做，这也行不通，

 PHFetchOptions *fetchOptions = [PHFetchOptions new]; fetchOptions.predicate = [NSPredicate predicateWithFormat:@"(mediaSubtype & %d) == 0", PHAssetMediaSubtypeVideoHighFrameRate]; 

有人请帮忙。 提前致谢。

 Unsupported predicate in fetch options: mediaSubtype == 131072 

Answer 1

尝试这个：

 fetchOptions.predicate = [NSPredicate predicateWithFormat:@"(mediaSubtype != %d)", PHAssetMediaSubtypeVideoHighFrameRate]; 

Answer 2

为了排除慢动作video，唯一对我有效的谓词是：

 PHFetchOptions *options = [PHFetchOptions new]; // Disable slow motion videos options.predicate = [NSPredicate predicateWithFormat:@"NOT ((mediaSubtype & %d) != 0)", PHAssetMediaSubtypeVideoHighFrameRate]; 

Answer 3

斯威夫特4

 let assetFetchOptions = PHFetchOptions() assetFetchOptions.predicate = NSPredicate(format: "NOT ((mediaSubtype & %d) != 0)", PHAssetMediaSubtype.videoHighFrameRate.rawValue)