iPhone-Sqlite：约束失败的错误

这是我的代码：

- (void) addOrder { if(addStmt == nil) { const char *sql = "insert into item(menuid,itemName,price,quantity,spiciness) Values( ?, ?, ?, ?,?)"; if(sqlite3_prepare_v2(database, sql, -1, &addStmt, NULL) != SQLITE_OK) NSAssert1(0, @"Error while creating add statement. '%s'", sqlite3_errmsg(database)); } // NSLog(@"ADDSTMT:%@",addStmt); sqlite3_bind_int(addStmt, 1, [menuID integerValue]); sqlite3_bind_text(addStmt, 2, [itemName UTF8String], -1, SQLITE_TRANSIENT); sqlite3_bind_double(addStmt, 3, price ); sqlite3_bind_int(addStmt, 4, [quantity integerValue]); sqlite3_bind_text(addStmt, 5, [spiciness UTF8String],-1,SQLITE_TRANSIENT); if(SQLITE_DONE != sqlite3_step(addStmt)) NSAssert1(0, @"Error while inserting data. '%s'", sqlite3_errmsg(database)); else menuID = [NSDecimalNumber numberWithLongLong:sqlite3_last_insert_rowid(database)]; //Reset the add statement. sqlite3_reset(addStmt); } 

这里数据被插入到数据库中，但得到错误“Constraint Failed”

Answer 1

嗨可能这个代码将帮助你。 用这种样式插入数据。

 sqlite3_stmt *stment; stment =nil; NSString *sql=[NSString stringWithFormat:@"insert into DateSave(Date,Name) Values('%@','%@')",Date,strTestName]; if (sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) { if (sqlite3_prepare_v2(database, [sql UTF8String], -1, &stment, NULL) == SQLITE_OK) { sqlite3_step(stment); testID =sqlite3_last_insert_rowid(database); } } sqlite3_finalize(stment); sqlite3_close(database);