为iPhone 5加载不同的Storyboard @app启动

我在我的AppDelegate.m中使用下面的代码来检测用户正在使用哪个设备：

- (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { if(UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) { CGSize result = [[UIScreen mainScreen] bounds].size; if(result.height == 480) { NSLog(@"iPhone 3,5 Inch"); [UIStoryboard storyboardWithName:@"MainStoryboard_iPhone" bundle:nil]; } if(result.height == 568) { NSLog(@"iPhone 4 Inch"); [UIStoryboard storyboardWithName:@"iPhone5-storyboard" bundle:nil]; } } return YES; } 

但是当我构build应用程序的NSLog显示，但没有故事板即将上演…

• 部署信息中的主要Storyboard字段为空，以便代码决定要加载的内容…

可以帮助我吗？

Thx和来自德国的问候

劳伦兹:)

Answer 1

这是我现在在其他职位上find的一种方式：

 if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone) { // The iOS device = iPhone or iPod Touch CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size; UIViewController *initialViewController = nil; if (iOSDeviceScreenSize.height == 480) { // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured) // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35 UIStoryboard *iPhone35Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone35" bundle:nil]; // Instantiate the initial view controller object from the storyboard initialViewController = [iPhone35Storyboard instantiateInitialViewController]; } if (iOSDeviceScreenSize.height == 568) { // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured) // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4 UIStoryboard *iPhone4Storyboard = [UIStoryboard storyboardWithName:@"Storyboard_iPhone4" bundle:nil]; // Instantiate the initial view controller object from the storyboard initialViewController = [iPhone4Storyboard instantiateInitialViewController]; } // Instantiate a UIWindow object and initialize it with the screen size of the iOS device self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; // Set the initial view controller to be the root view controller of the window object self.window.rootViewController = initialViewController; // Set the window object to be the key window and show it [self.window makeKeyAndVisible]; } else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad) { // The iOS device = iPad UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController; UINavigationController *navigationController = [splitViewController.viewControllers lastObject]; splitViewController.delegate = (id)navigationController.topViewController; }