Tag: uigesturerecognizer

需要应用UIRotationGestureRecognnizer，然后是UILongPressGestureRecongnizer: 在一个视图上应用UILongPressGestureRecongnizer ，请查看以下代码以供参考。 @interface ViewController () { UIRotationGestureRecognizer *rotationGestureRecognizer6; } – (void)viewDidLoad { //——–Added LongPress Gesture———-// UILongPressGestureRecognizer *longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleLongPress:)]; longPress.minimumPressDuration = 2.0; [view6 addGestureRecognizer:longPress]; rotationGestureRecognizer6 = [[UIRotationGestureRecognizer alloc] initWithTarget:self action:@selector(handleRotationWithGestureRecognizer:)]; } #pragma mark – UILongPressGesture Handler Method -(void)handleLongPress:(UILongPressGestureRecognizer *)sender { if (sender.state == UIGestureRecognizerStateEnded) { NSLog(@"UIGestureRecognizerStateEnded"); } else if (sender.state == UIGestureRecognizerStateBegan){ […]

UIPanGestureRecognizer没有启动。 Swift 3: 我的视图层次如下：视图查看用户的Img + Emoji（A）与UI元素的视图。（B）在viewDidLoad中，我为emojis创buildUIImageViews，将它们添加到A并添加手势识别器（平移，缩放，旋转）： let emojiView = UIImageView(image: emoji) emojiView.tag = n emojiView.frame = CGRect(x: 153, y: 299, width: 70, height: 70) emojiView.isUserInteractionEnabled = true let pan = UIPanGestureRecognizer(target: self, action: #selector(self.handlePan(recognizer:))) pan.delegate = self emojiView.addGestureRecognizer(pan) let pinch = UIPinchGestureRecognizer(target: self, action: #selector(self.handlePinch(recognizer:))) pinch.delegate = self emojiView.addGestureRecognizer(pinch) let rotate = UIRotationGestureRecognizer(target: […]

手势识别器不叫: 当用户在文本框之外轻击时，我已经设置了一个用于解除键盘的手势识别器。 DismissKeyboard函数不会被调用。我是否设置了观察者错误还是这是一个不同的问题？另外，这是一个正在挖掘的桌面视图。代码摘录 class CommentsViewController: UIViewController, UITableViewDelegate, UITableViewDataSource { override func viewDidAppear(animated: Bool) { super.viewDidAppear(animated) NSNotificationCenter.defaultCenter().addObserver(self, selector: Selector("keyboardWillShow:"), name: UIKeyboardWillShowNotification, object: nil) NSNotificationCenter.defaultCenter().addObserver(self, selector: Selector("keyboardWillHide:"), name: UIKeyboardWillHideNotification, object: nil) } func keyboardFrameChanged(notification: NSNotification) { println("keyboardFrameChanged") let userInfo = notification.userInfo let key = UIKeyboardFrameEndUserInfoKey if let info = userInfo { let frameValue = info[key] […]

iOS / Swift：如何实现backButton的longPressed动作？: 我试图为我的应用程序中的每个ViewController实现自定义后退button 。我希望它有两个行动。如果button被轻敲，它应该正常行为，并上升导航堆栈。如果button按下的时间更长，它应该转到预定义的ViewController。我怎么才能做到这一点，只有后退快速？

将GestureRecogniser附加到多个图像浏览: 今天遇到的一些奇怪的事情，同时将同一个手势识别器连接到多个图像视图。它只附加到最后一个，换句话说，它可以附加到只有一个视图！我不得不创build多个手势识别器来满足我的要求。以下是我所做的。我正确吗？这是将识别器附加到多个图像视图的唯一方法吗？请注意，我不想使用UITableView或UIVIew，并把所有的图像，并附加手势识别器只有UITableView或UIVIew。我有所有图像分散，我必须检测哪个图像被拖动。谢谢。 [imgView1 setUserInteractionEnabled:YES]; [imgView1 setMultipleTouchEnabled:YES]; [imgView2 setUserInteractionEnabled:YES]; [imgView2 setMultipleTouchEnabled:YES]; [imgView3 setUserInteractionEnabled:YES]; [imgView3 setMultipleTouchEnabled:YES]; [imgView4 setUserInteractionEnabled:YES]; [imgView4 setMultipleTouchEnabled:YES]; [imgView5 setUserInteractionEnabled:YES]; [imgView5 setMultipleTouchEnabled:YES]; [imgView6 setUserInteractionEnabled:YES]; [imgView6 setMultipleTouchEnabled:YES]; //Attach gesture recognizer to each imagviews gestureRecognizer1 = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(gestureHandler:)]; gestureRecognizer1.delegate = self; gestureRecognizer2 = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(gestureHandler:)]; gestureRecognizer2.delegate […]

从UITapGestureRecognizer中移除目标: 我已经为我的手势识别器添加了一个匿名方法的动作 UITapGestureRecognizer tapGesture = new UITapGestureRecognizer (); tapGesture.AddTarget (() => HandleTap (tapGesture)); 我怎样才能删除目标？ UIGestureRecognizer.Token是必需的。

UILongPressGestureRecognizer不起作用: 我想检测UILongPressGestureRecognizer的UIWebView并按住..如果我长按近3秒，那么下面的条件应该是True然后只 if (navigationType == UIWebViewNavigationTypeLinkClicked && longGesture )但它不工作….它继续在循环中每次..不检查longPressGesture时间… 即使我已经试过条件.. if (navigationType == UIWebViewNavigationTypeLinkClicked && longGesture.minimumPressDuration> 3 ) 不工作..我在犯错误的地方.. – (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType { UILongPressGestureRecognizer *longGesture = [[UILongPressGestureRecognizer alloc] init]; longGesture.numberOfTapsRequired = 1; longGesture.numberOfTouchesRequired = 1; longGesture.minimumPressDuration = 3 ; longGesture.delegate = self; // longGesture.allowableMovement = 50; [self.webView addGestureRecognizer:longGesture]; if (navigationType == UIWebViewNavigationTypeLinkClicked && […]

iOS：在UI（子）视图中处理UIGestureRecognisers: 我想知道如何最好地解决以下问题：我有一个单一的ViewController。它的视图包含大量复杂的子视图（UIView的子类）。由于这些UIViews的复杂性，初始化他们自己的UIGestureRecognisers并且执行相应的目标动作。由于我想协调各种子视图的手势，我必须将单个ViewController设置为手势的委托。这有很多种可能性。 1）初始化viewController中的所有手势（这将导致大量的viewController） 2）在UIVIews（getViewController）中定义一个协议，由ViewController实现 @protocol CustomViewDelegate <NSObject> @required – (UIViewController *)getViewController; @end 3）自定义UIViews的init方法，并使用ViewController作为选项。 – (id)initWithFrame:(CGRect)frame andViewController:(UIViewController *)vc; 解决这个问题最高雅的可能性是什么？在UIView对象中实现目标动作可以吗？感谢您的想法…

locationOfTouch和numberOfTouches: 嗨我有这个识别器，设置2触摸，但它只返回一个，而不是两个CGPoint -(void)gestureLoad { UIGestureRecognizer *recognizer; recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(numTap2:)]; [(UITapGestureRecognizer *)recognizer setNumberOfTouchesRequired:2]; [self.view addGestureRecognizer:recognizer]; self.tapRecognizer = (UITapGestureRecognizer *)recognizer; recognizer.delegate = self; [recognizer release]; } – (void)numTap2:(UITapGestureRecognizer *)recognizer { CGPoint location = [recognizer locationInView:self.view]; NSLog(@"x %fy %f",location.x, location.y); } 据我所知，我用这两种方法循环触摸的数量，但我还没有想出如何： -(CGPoint)locationOfTouch:(NSUInteger)touchIndex inView:(UIView *)view { } -(NSUInteger)numberOfTouches { } 非常感谢！

如何让tableViewCell同时处理tap和longPress？: 我把它放在cellForRowAtIndexPath中 let longPress = UILongPressGestureRecognizer(target: self, action: #selector(CalorieCountViewController.handleLongPress)) cell.addGestureRecognizer(longPress) longPress.cancelsTouchesInView = true let tapPress = UITapGestureRecognizer(target: self, action: #selector(CalorieCountViewController.handleTapPress)) cell.addGestureRecognizer(tapPress) tapPress.cancelsTouchesInView = true 并将这些代码（下面的代码）放在它的外面，并完全删除didSelectRowAtIndexPath函数，而是使用indexPathForSelectedRow来获取刚刚select的行用户。 func handleLongPress(sender: UILongPressGestureRecognizer){ let index = tableView.indexPathForSelectedRow! doSomething(index) } func handleTapPress(sender: UITapGestureRecognizer){ let index = tableView.indexPathForSelectedRow! doSomethingElse(index) } 结果indexPathForSelectedRow返回nil，但我没有select一行，并且在我的代码中没有任何“deselectRowAtIndexPath”。