获取两个date之间的天名称在iOS？

如何获取iOS中两个date之间的天数名称？

例：

input：
 开始date：2012年3月3日 
 结束date：2012年5月11日

输出：
  3-11-2012星期三
  4-11-2012星期四
  5-11-2012星期五

谢谢..

Answer 1

尝试这个，

  NSDateFormatter *df = [[NSDateFormatter alloc] init]; [df setDateFormat:@"yyyy-MM-dd"]; NSDate *startDate = [df dateFromString:@"2012-07-20"]; // your start date NSDate *endDate = [NSDate date]; // your end date NSDateComponents *dayDifference = [[NSDateComponents alloc] init]; NSMutableArray *dates = [[[NSMutableArray alloc] init] autorelease]; NSUInteger dayOffset = 1; NSDate *nextDate = startDate; do { [dates addObject:nextDate]; [dayDifference setDay:dayOffset++]; NSDate *d = [[NSCalendar currentCalendar] dateByAddingComponents:dayDifference toDate:startDate options:0]; nextDate = d; } while([nextDate compare:endDate] == NSOrderedAscending); [df setDateStyle:NSDateFormatterFullStyle]; for (NSDate *date in dates) { NSLog(@"%@", [df stringFromDate:date]); } [df release]; 

输出是 ：

 Friday, July 20, 2012 Saturday, July 21, 2012 Sunday, July 22, 2012 Monday, July 23, 2012 Tuesday, July 24, 2012 

Answer 2

检查此解决scheme：

 NSDateComponents *components; NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init]; [dateFormat setDateFormat:@"dd-MM-yyyy"]; NSDate *startDate = [dateFormat dateFromString:@"3-11-2012"]; NSDate *endDate = [dateFormat dateFromString:@"5-11-2012"]; [dateFormat setDateFormat:@"dd-MM-yyyy, EEEE"]; components = [[NSCalendar currentCalendar] components:NSDayCalendarUnit fromDate:startDate toDate:endDate options:0]; int days = [components day]; for (int x = 0; x <= days; x++) { NSLog(@"%@", [dateFormat stringFromDate:startDate]); startDate = [startDate dateByAddingTimeInterval:(60 * 60 * 24)]; } 

输出是：

 03-11-2012, Saturday 04-11-2012, Sunday 05-11-2012, Monday 

Answer 3

这是你需要的：

 NSDateFormatter *inputFormatter = [[NSDateFormatter alloc] init]; [inputFormatter setDateFormat:@"mm-dd-yyyy"]; NSDate *inputDate = [inputFormatter dateFromString:@"3-11-2012"]; NSDateFormatter *outputFormatter = [[NSDateFormatter alloc] init]; [outputFormatter setDateFormat:@"mm-dd-yyyy EEEE"]; NSString *output = [outputFormatter stringFromDate:inputDate]; NSLog(@"%@",output); [inputFormatter release]; [outputFormatter release]; 

Answer 4

这是一个办法：

 NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar]; NSDateComponents *dateComponents = [[NSDateComponents alloc] init]; [dateComponents setYear:2012]; [dateComponents setMonth:11]; [dateComponents setDay:03]; NSDate *date1 = [gregorianCalendar dateFromComponents:dateComponents]; [dateComponents setYear:2012]; [dateComponents setMonth:11]; [dateComponents setDay:05]; NSDate *date2 = [gregorianCalendar dateFromComponents:dateComponents]; NSDateFormatter *outputDateFormatter = [[NSDateFormatter alloc] init]; [outputDateFormatter setDateFormat:@"dd-MM-yyyy EEEE"]; NSDate *dayDate; dayDate = date1; NSLog(@"%@", [outputDateFormatter stringFromDate:dayDate]); do { dayDate = [dayDate dateByAddingTimeInterval:86400]; NSLog(@"%@", [outputDateFormatter stringFromDate:dayDate]); } while ([dayDate compare:date2]==NSOrderedAscending); 

使用NSCalendar为您（和您的用户）提供了更大的显示和操作date的灵活性。