检查时间和date是否在特定date和时间之间
我有3个variables;
开学date – Wed Apr 12 – Wed Jun 11 11.00 am from 11.00 pm上课时间 – 11.00 am from 11.00 pm 。 （这是一个string，11AM是开始时间，12PM是结束时间）
1.）现在，我需要获取当前date和时间（ [NSDate date] ），并检查当前date是否介于startDate和endDate之间，然后检查当前时间是否在timeDuration之间（如11.00am from 11.00pm ）
2.）如果当前时间在持续时间之间（在11.00 am from 11.00 pm ），我需要计算下列情况的剩余时间;
a）如果时间是上午10点，我需要计算开始时间的11.00am时间。 （答案是1 hour ）。
b）如果时间是11.00am时11.45AM ，由于时间大于开始时间（ 11.00am ），我需要计算剩余时间到结束时间（即11.00pm ）。
c）如果时间是11.45pm时11.45pm ，由于时间大于结束时间（即11.00pm ），我需要打印一个NSLog，说'超时'。
基本的想法是将您的startDate和endDate转换为实际的NSDate ，并将它们与当前date进行比较。 然后，如果当前date在适当的范围内，则将开始和结束时间添加到当前date，以便为开始和结束时间提供特定的时间点。 一旦你有了这些date，你可以使用NSDate的compare和timeIntervalSinceDate方法来获得你需要的值：
// NOTE: NO error checking is being done in this code. // Starting variables NSString *startDateString = @"Wed Apr 12"; NSString *endDateString = @"Wed Jun 11"; NSString *timeDurationString = @"11.00 am from 11.00 pm"; // Get the current date NSDate *currentTime = [NSDate date]; NSCalendar *cal = [NSCalendar currentCalendar]; NSDateComponents *currentDateComps = [cal components:NSYearCalendarUnit|NSMonthCalendarUnit|NSDayCalendarUnit fromDate:currentTime]; // Add the current year onto our date string NSString *startDateStringWithYear = [NSString stringWithFormat:@"%@ %d", startDateString, currentDateComps.year]; NSString *endDateStringWithYear = [NSString stringWithFormat:@"%@ %d", endDateString, currentDateComps.year]; // Calculate NSDate's for start/endDate NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; [formatter setDateFormat:@"EEE MM dd yyyy"]; NSDate *startDate = [formatter dateFromString:startDateStringWithYear]; NSDate *endDate = [formatter dateFromString:endDateStringWithYear]; // Return if today's date is not between the start and end dates if ([startDate compare:currentTime] == NSOrderedDescending || [endDate compare:currentTime] == NSOrderedAscending) { return; } // Break the timeDurationString into separate words NSArray *timeDurationStringWords = [timeDurationString componentsSeparatedByString:@" "]; // Calculate NSDate's for the start time for today: NSString *startTimeString = [timeDurationStringWords objectAtIndex:0]; currentDateComps.hour = [[startTimeString substringToIndex:2] intValue]; currentDateComps.minute = [[startTimeString substringFromIndex:3] intValue]; if ([[timeDurationStringWords objectAtIndex:1] isEqualToString:@"pm"]) { currentDateComps.hour += 12; } NSDate *startTime = [cal dateFromComponents:currentDateComps]; // And now the end time for today NSString *endTimeString = [timeDurationStringWords objectAtIndex:3]; currentDateComps.hour = [[endTimeString substringToIndex:2] intValue]; currentDateComps.minute = [[endTimeString substringFromIndex:3] intValue]; if ([[timeDurationStringWords objectAtIndex:4] isEqualToString:@"pm"]) { currentDateComps.hour += 12; } NSDate *endTime = [cal dateFromComponents:currentDateComps]; // Now we have what we really want: A specific start time, current time, and end time. // Check to see if we are waiting to start: if ([startTime compare:currentTime] == NSOrderedDescending) { NSTimeInterval minutesToStartTime = [startTime timeIntervalSinceDate:currentTime] / 60; NSLog(@"Start time is in %02d+%02d", (int)(minutesToStartTime / 60), (int)minutesToStartTime % 60); return; } // Check to see if we are late: if ([endTime compare:currentTime] == NSOrderedAscending) { NSLog(@"Time Exceeded"); return; } // We are between the two times: NSTimeInterval minutesToEndTime = [endTime timeIntervalSinceDate:currentTime] / 60; NSLog(@"End time is in %02d+%02d", (int)(minutesToEndTime / 60), (int)minutesToEndTime % 60);
你可以使用- (NSComparisonResult)compare:(NSDate *)anotherDate
比较当前datestartDate和endDate。
NSComparisonResult enum { NSOrderedAscending = -1, NSOrderedSame, NSOrderedDescending };
例：
NSDate *currentDate = [NSDate date]; if (([currentDate compare:startDate ] == NSOrderedDescending) && ([currentDate compare:endDate ] == NSOrderedAscending)) { //currentDate is between startDate and endDate. }
或者通过bbum来看看这个解决scheme。