使用AVAudioPlayer播放多个audio文件

我在主StoryBoard上创build了3个UIButtons。

当我按下“button1”或“button2”时，每个播放audio文件（“播放器1”，“播放器2”）。当audio播放时，UIButton被设置为selected 。

我想“Button3”在一行中实现多个函数。 这意味着当我按下“button3”时，应该首先播放“播放器3”，然后在“播放器1”之后播放“播放器2”。

然而，当我按下“Button3”时，同时播放“播放器1”和“播放器2”，因为前一个结束没有延迟。

我发现设置AVAudioPlayer的代理或使用AVQueuePlayer将解决这个问题，但是我发现很难做出改变。

  fileprivate var player1:AVAudioPlayer? fileprivate var player2:AVAudioPlayer? fileprivate var player3:AVAudioPlayer? @IBAction func pushButton1(sender: UIButton) { audioPlayer1(url: url1) } @IBAction func pushButton2(sender: UIButton) { audioPlayer2(url: url2) } @IBAction func pushButton3(_ sender: UIButton) { audioPlayer3(url: url1, url2: url2, url3: url3) } func audioPlayerDidFinishPlaying(_ player: AVAudioPlayer, successfully flag: Bool) { if (player === player1) { yourButton1.isSelected = false } else if (player === player2) { yourButton2.isSelected = false } else if (player === player3) { //"player 1" and "player 2" are played at same time yourButton3.isSelected = false player1!.play() yourButton1.isSelected = true player2!.play() yourButton2.isSelected = false } } func audioPlayer1(url: URL) { do { try player1 = AVAudioPlayer(contentsOf:url) player1!.play() yourButton1.isSelected = true player1!.delegate = self } catch { print(error) } } func audioPlayer2(url: URL) { do { try player2 = AVAudioPlayer(contentsOf:url) player2!.play() yourButton2.isSelected = true player2!.delegate = self } catch { print(error) } } func audioPlayer3(url: URL, url2: URL, url3: URL) { do { try player3 = AVAudioPlayer(contentsOf:url3) try player1 = AVAudioPlayer(contentsOf: url1) try player2 = AVAudioPlayer(contentsOf: url2) player3!.play() yourButton3.isSelected = true player3!.delegate = self player1!.delegate = self } catch { print(error) } } } 

更改了代码

  var queue = AVQueuePlayer() var items = [AVPlayerItem]() override func viewDidLoad() { super.viewDidLoad() player1?.delegate = self player2?.delegate = self player3?.delegate = self let asset1 = AVPlayerItem(url: url1) let asset2 = AVPlayerItem(url: url2) let asset3 = AVPlayerItem(url: url3) let asset4 = AVPlayerItem(url: url4) items = [asset1, asset2, asset3, asset4] queue = AVQueuePlayer(items: items) for item in queue.items() { NotificationCenter.default.addObserver(self, selector: #selector(playerItemDidReachEnd(notification:)), name: .AVPlayerItemDidPlayToEndTime, object: item) } } @IBAction func pushButton3(_ sender: UIButton) { //audioPlayer3(url: url1, url2: url2) sender.isSelected = true queue.play() } func playerItemDidReachEnd(notification: NSNotification) { if notification.object as? AVPlayerItem == items[0] { yourButton3.isSelected = false yourButton1.isSelected = true } if notification.object as? AVPlayerItem == items[1] { yourButton1.isSelected = false yourButton2.isSelected = true } if notification.object as? AVPlayerItem == items[2] { yourButton2.isSelected = false yourButton4.isSelected = true //yourButton1.isSelected = true } if notification.object as? AVPlayerItem == items[3] { yourButton4.isSelected = false print("item 3") } 

Answer 1

编辑： 这是 AVAudioPlayer 的方法

所以基本上：

1：只添加一名玩家，移除其余的玩家。

2：用您想要播放的对象创build一个 NSMutableArray 。

3：根据按下的button，你可以重新安排NSMutableArray对象来设置正确的顺序，如你所愿。 （如果你想简单地重新创build数组），然后开始播放数组中的firstObject （url），并将其添加到播放器中。

4：玩家完成游戏后，可以像上面那样开始播放下一个将NSMutableArray添加到玩家的对象。

以上步骤将避免多个玩家同时玩，以及其他好处（如避免同时加载多个URL等）

您可能需要一些variables来检查currentPlayingObject以确定下一个是哪一个，也可能是一个int ，并检查是否不尝试从数组中加载新项目（如果它是最后一个项目），以避免在访问objectAtIndex时发生崩溃那不存在。