使用当前时间计算arrays的最近时间

我有时间的数组中有6个对象

NSMutableArray *time=[[NSMutableArray alloc]initwithObjects:12:30, 14:40, 16:50, 20:30, 21:49, 23:12,nil]; Current time = 17:12; 

我应该如何计算距离time_array 8:12的最近时间？

 conclusion must be 20:30 

我实现了许多公式，比如在减去时间后得到最less的可用值，但是存在一些缺陷，并不是一个完美的解决scheme。 目标C中的任何一个人有没有想法来计算完美的最近时间？

我已经试过了

  //// Calculating to fetch nearest time NSDateFormatter *current_time_format = [[NSDateFormatter alloc] init]; [current_time_format setTimeZone:zone]; [current_time_format setDateFormat:@"HHmm"]; NSString *current_date_string=[current_time_format stringFromDate:[NSDate date]]; int current_time_int=[current_date_string intValue]; int nearest_time=10000; int time_calculation=0; if ([calculated_time_array count]>=6) { [calculated_time_array removeAllObjects]; } for (int i=0; i<[current_timings_array count]; i++) { NSString *prayer_timings=[current_timings_array objectAtIndex:i]; prayer_timings=[prayer_timings stringByReplacingOccurrencesOfString:@":" withString:@""]; time_calculation=[prayer_timings intValue]-current_time_int; NSLog(@"%d-%d=%d",[prayer_timings intValue],current_time_int,time_calculation); NSString *length_value=[NSString stringWithFormat:@"%d",current_time_int]; NSLog(@"lenght_value= %d",[length_value length]); [calculated_time_array addObject:[NSString stringWithFormat:@"%d",time_calculation]]; if (time_calculation<nearest_time && time_calculation>0) { nearest_time=time_calculation; } NSString *time_string=[NSString stringWithFormat:@"%d",nearest_time]; int index=[calculated_time_array indexOfObject:time_string]; header_bg_image.image=[UIImage imageNamed:[NSString stringWithFormat:@"top%d_bg.png",index+1]]; NSMutableString *mu = [NSMutableString stringWithString:[NSString stringWithFormat:@"%d",nearest_time]]; if ([time_string length]==3) { [mu insertString:@"0" atIndex:0]; [mu insertString:@":" atIndex:2]; } NSString *time=[NSString stringWithFormat:@"%@",mu]; time=[current_timings_array objectAtIndex:index]; time=[time stringByReplacingOccurrencesOfString:@":" withString:@"."]; NSDate *date1; NSDate *date2; { NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; [formatter setDateFormat:@"hh.mm"]; date1 = [formatter dateFromString:time]; date2 = [formatter dateFromString:[formatter stringFromDate:[NSDate date]]]; } // Here I'm calculating the time difference NSTimeInterval interval = [date1 timeIntervalSinceDate: date2];//[date1 timeIntervalSince1970] - [date2 timeIntervalSince1970]; int hour = interval / 3600; int minute = (int)interval % 3600 / 60; // NSLog(@"%@ %dh %dm", interval<0?@"-":@"+", ABS(hour), ABS(minute)); label_time_left.text=[NSString stringWithFormat:@"Time left %dh %dm",ABS(hour), ABS(minute)]; 

Answer 1

我用自己的方法解决了这个问题，在这里它可以帮助别人

  NSDate *date = [NSDate date]; NSDateFormatter *formatter = [[NSDateFormatter alloc] init]; [formatter setTimeZone:zone]; [formatter setDateFormat:@"HHmm"]; current_time=[formatter stringFromDate:date]; int current_time_int=[current_time intValue]; nearest_time=2400; for (int i=0; i<[current_timings_array count]; i++) { NSString *prayer_timings=[current_timings_array objectAtIndex:i]; prayer_timings=[prayer_timings stringByReplacingOccurrencesOfString:@":" withString:@""]; int calculated_time=[prayer_timings intValue]-current_time_int; NSLog(@"Nearest Timings %d-%d=%d",[prayer_timings intValue],current_time_int ,calculated_time); NSString *last_object_time=[current_timings_array.lastObject stringByReplacingOccurrencesOfString:@":" withString:@""]; if (current_time_int>[last_object_time intValue]) { NSLog(@"It is greated value %d",[last_object_time intValue]); if (calculated_time<nearest_time ) { nearest_time=calculated_time; header_bg_image.image=[UIImage imageNamed:[NSString stringWithFormat:@"top%d_bg.png", i+1]]; } } else{ if (calculated_time<nearest_time && calculated_time>0) { nearest_time=calculated_time; header_bg_image.image=[UIImage imageNamed:[NSString stringWithFormat:@"top%d_bg.png", i+1]]; } } } 

Answer 2

我假设你的数组中有NSDate对象。 你可以做一个循环：

 NSDate *minDate = time.lastObject; NSTimeInterval minTimeInterval = [minDate timeIntervalSince1970]; NSTimeInterval current = [[NSDate date] timeIntervalSince1970]; for (NSDate *date in time) { NSTimeInterval interval = [date timeIntervalSince1970]; if (labs(minTimeInterval - current) > labs(interval - current)) { minDate = date; minTimeInterval = interval; } } // The minDate is the object you are looking for