为什么披露指标不显示?

当应用程序运行在模拟器披露指标不显示。因此,我不能去详细

NamesTableViewController.m:

#import "NamesTableViewController.h" @interface NamesTableViewController () @property (nonatomic, copy) NSDictionary *propertyList; @property (nonatomic, copy) NSArray *letters; @property (nonatomic, copy)NSMutableArray *filteredNames; @property (nonatomic, strong)UISearchController *searchController; @end @implementation NamesTableViewController @synthesize propertyList, letters, filteredNames, searchController; - (void)viewDidLoad { [super viewDidLoad]; UITableView *tableView = (id)[self.view viewWithTag:1]; [tableView registerClass:[UITableViewCell class] forCellReuseIdentifier:@"Cell"]; filteredNames = [[NSMutableArray alloc]init]; searchController = [[UISearchController alloc]init]; //bura bax self yigishdir self.searchController.searchResultsUpdater = self; NSString *path = [[NSBundle mainBundle] pathForResource:@"names" ofType:@"plist"]; self.propertyList = [NSDictionary dictionaryWithContentsOfFile:path]; self.letters = [[self.propertyList allKeys] sortedArrayUsingSelector:@selector(compare:)]; } #pragma mark - Table view data source - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { if (tableView.tag == 1){ return self.letters.count; }else { return 1; } } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { if (tableView.tag == 1) { NSString *letter = self.letters[section]; NSArray *keyValues = [self.propertyList[letter] allKeys]; return keyValues.count; } else { return [filteredNames count]; } } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath]; // Configure the cell... if (tableView.tag == 1){ NSString *letter = self.letters[indexPath.section];; NSArray *keyValues = [[self.propertyList[letter] allKeys] sortedArrayUsingSelector:@selector(compare:)]; cell.textLabel.text = keyValues[indexPath.row]; } else{ cell.textLabel.text = filteredNames[indexPath.row]; } return cell; } -(NSArray *)sectionIndexTitlesForTableView:(UITableView *)tableView { return self.letters; } -(NSString*)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { if (tableView.tag == 1) { return letters [section]; } else { return nil; } } #pragma mark Search Display Delegate Methods -(void)searchDisplayController:(UISearchController *)controller didLoadSearchResultsTableView:(UITableView *)tableView { [tableView registerClass:[UITableViewCell class] forCellReuseIdentifier:@"Cell"]; } -(BOOL)searchDisplayController:(UISearchController *)controller shouldReloadTableForSearchString:(NSString *)searchString { [filteredNames removeAllObjects]; if (searchString.length > 0) { NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF contains [search] %@", self.searchBar.text]; for (NSString *letter in letters) { NSArray *matches = [[self.propertyList[letter] allKeys]filteredArrayUsingPredicate:predicate]; [filteredNames addObjectsFromArray:matches]; } } return YES; } @end 

NamesTableViewController.h:

 #import <UIKit/UIKit.h> @interface NamesTableViewController : UITableViewController <UISearchDisplayDelegate, UISearchBarDelegate> @property (strong, nonatomic) IBOutlet UISearchBar *searchBar; @end 

我怎么能做到这一点?请帮助我。 我是新的

尝试这个

 - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier forIndexPath:indexPath]; cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator; ....... } 

更新

  - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { // Navigation logic may go here, for example: If your are used in connection // use this [self performSegueWithIdentifier:@"yourSegueName" sender:self]; // if you are used connection less in storyboard , use this DetailViewController *vc = [self.storyboard instantiateViewControllerWithIdentifier:@"DetailViewController"]; // Push the view controller. [self.navigationController pushViewController:vc animated:YES]; }