如何快速传递多个值与通知

如何通过通知发送一个数字和一个string…

let mynumber=1; let mytext="mytext"; NSNotificationCenter.defaultCenter().postNotificationName("refresh", object: ?????????????); 

并在接收器中接收值？

 func refreshList(notification: NSNotification){ let receivednumber=?????????? let receivedString=????????? } 

Answer 1

你可以把它们包装在一个NSArray或一个NSDictionary或一个自定义对象中。

例如：

 let mynumber=1; let mytext="mytext"; let myDict = [ "number": mynumber, "text":mytext] NSNotificationCenter.defaultCenter().postNotificationName("refresh", object:myDict); func refreshList(notification: NSNotification){ let dict = notification.object as! NSDictionary let receivednumber = dict["number"] let receivedString = dict["mytext"] } 

Answer 2

Xcode 8.3.1•Swift 3.1

 extension Notification.Name { static let refresh = Notification.Name("refresh") } 

---

 let myDict: [String: Any] = ["myInt": 1, "myText": "text"] NotificationCenter.default.post(name: .refresh, object: myDict) 

---

 NotificationCenter.default.addObserver(self, selector: #selector(refreshList), name: .refresh, object: nil) // don't forget vvv add an underscore before the view controller method parameter func refreshList(_ notification: Notification) { if let myDict = notification.object as? [String: Any] { if let myInt = myDict["myInt"] as? Int { print(myInt) } if let myText = myDict["myText"] as? String { print(myText) } } } 

Answer 3

使用userInfo

 NSNotificationCenter.defaultCenter().postNotificationName("refresh", object: nil, userInfo: ["number":yourNumber, "string":yourString] 

并检索：

 func refreshList(notification: NSNotification){ let userInfo = notification.userInfo as Dictionary let receivednumber = userInfo["number"] let receivedString = userInfo["string"] } 

我不是很快（未经testing），但你明白了。

Answer 4

其实有很多方法可以做到这一点。 其中之一是传递一组对象，如：

 let arrayObject : [AnyObject] = [mynumber,mytext] NSNotificationCenter.defaultCenter().postNotificationName("refresh", object: arrayObject) func refreshList(notification: NSNotification){ let arrayObject = notification.object as! [AnyObject] let receivednumber = arrayObject[0] as! Int let receivedString = arrayObject[1] as! String } 

Answer 5

Swift 4.0，我通过单键：值，你可以添加多个键和值。

  NotificationCenter.default.post(name:NSNotification.Name(rawValue: "updateLocation"), object: ["location":"India"]) 

添加观察者和方法定义

 NotificationCenter.default.addObserver(self, selector: #selector(getDataUpdate), name: NSNotification.Name(rawValue: "updateLocation"), object: nil) @objc func getDataUpdate(notification: Notification) { guard let object = notification.object as? [String:Any] else { return } let location = object["location"] as? String self.btnCityName.setTitle(location, for: .normal) print(notification.description) print(notification.object ?? "") print(notification.userInfo ?? "") }