如何将textfield的值带入其他viewController在xcode的对象？
我有这个电子邮件='abc'和pw ='123'值在PHP MySQL数据库和PHP代码如下。
login2.php
<?php $connect = mysqli_connect("localhost","","",""); if(isset($_POST['email'])) { $email = $_POST['email']; $pw = $_POST['pw']; $sql = "SELECT * FROM table WHERE email='$email' AND pw=md5('$pw')"; $get = mysqli_query($connect,$sql); if($get && mysqli_num_rows($get) > 0) { while($row = mysqli_fetch_assoc($get)) { $email_db = $row['email']; $pw_db = $row['pw']; echo '{"success":1}'; exit(); } mysqli_free_result($get); } else { echo '{"success":0}'; echo mysqli_error($connect); exit(); } } ?> 我想在xcode中实现的是将成功值带入其他ViewController，称为HomepageVC，并在单击loginbutton动作时显示值。
现在我只能查看相同的ViewController页面上的文本字段值。 我不知道如何将input值转移到另一个ViewController。 对象代码如下。
ViewController.m
@synthesize displayL,passL,email,pw; - (IBAction)loginbutton:(id)sender { @try { if([[email text] isEqualToString:@""] || [[pw text] isEqualToString:@""] ) { [self alertFailed:@"Please enter both Username and Password" :@"Login Failed!"]; } else { NSString *post =[[NSString alloc] initWithFormat:@"email=%@&pw=%@",[email text],[pw text]]; NSLog(@"PostData: %@",post); NSURL *url=[NSURL URLWithString:@"http://localhost/login2.php"]; NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/json" forHTTPHeaderField:@"Accept"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSError *error = [[NSError alloc] init]; NSHTTPURLResponse *response = nil; NSData *urlData=[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; NSLog(@"Response code: %d", [response statusCode]); if ([response statusCode] >=200 && [response statusCode] <300) { NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding]; NSLog(@"Response ==> %@", responseData); SBJsonParser *jsonParser = [SBJsonParser new]; NSDictionary *jsonData = (NSDictionary *) [jsonParser objectWithString:responseData error:nil]; NSLog(@"%@",jsonData); NSInteger success = [(NSNumber *) [jsonData objectForKey:@"success"] integerValue]; NSLog(@"%d",success); if(success == 1) { NSLog(@"Login SUCCESS"); [self alertStatus:@"Logged in Successfully." :@"Login Success!"]; NSString * input = email.text; NSString * input2 = pw.text; displayL.text = input; passL.text = input2; } else { NSString *error_msg = (NSString *) [jsonData objectForKey:@"error_message"]; [self alertFailed:error_msg :@"Login failed"]; } } else { if (error) NSLog(@"Error: %@", error); [self alertFailed:@"Connection Failed" :@"Login Failed!"]; } } } @catch (NSException * e) { NSLog(@"Exception: %@", e); [self alertStatus:@"Login Failed." :@"Login Failed!"]; } }
如果要将currentViewController的textfield值用于nextViewController ，则可以使用NSUserDefaults 。
将您的文本字段值存储在一个string中。 例如Txtfldstring
Txtfldstring= [NSString stringWithFormat:@"%@",_yourTextField.text];
然后像下面的方式存储该文本字段的值：
NSUserDefaults *prefs = [NSUserDefaults standardUserDefaults]; // saving an NSString [prefs setObject:Txtfldstring forKey:@"abc"];
在nextViewController或任何其他控制器中使用此值，如下所示：
NSUserDefaults *prefs = [NSUserDefaults standardUserDefaults]; // getting an NSString NSString *s = [prefs stringForKey:@"abc"]; NSLog(@“%@",s);