：无法识别的select器发送到实例…]

在我的iOS应用程序中，我创build了一个具有自定义单元格的表格视图控制器，其中一个包含一个PickerView。 这是自定义单元的类：

import Foundation import UIKit class PickerCell: UITableViewCell { @IBOutlet weak var label : UILabel! @IBOutlet weak var pickerView : UIPickerView! func configurePickerCell(labelText:String, pickerDelegate:MyPickerViewController, enabled:Bool, defaultValueIndex:Int) { self.label.text = labelText var labelFrame:CGRect = self.label.frame labelFrame.size.height = Settings.labelHeight self.label.frame = labelFrame self.pickerView.delegate = pickerDelegate self.pickerView.dataSource = pickerDelegate if (enabled) { self.pickerView.userInteractionEnabled = true } else { self.pickerView.userInteractionEnabled = false self.pickerView.selectRow(defaultValueIndex, inComponent: 0, animated: true) } } } 

这里是select器视图控制器类：

 import Foundation import UIKit class MyPickerViewController: UIViewController,UIPickerViewDataSource,UIPickerViewDelegate { var pickerData:[String]! init(pickerData: [String]){ super.init(nibName: nil, bundle: nil) self.pickerData = pickerData } required init(coder aDecoder: NSCoder) { super.init(coder: aDecoder) fatalError("init(coder:) has not been implemented") } func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int { return 1 } func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int { return pickerData.count } func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! { return pickerData[row] } func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) { println(self.pickerData[row]) } } 

并在我的表视图控制器中的一对方法：

 override func viewWillAppear(animated: Bool) { self.tabBarController?.navigationItem.leftBarButtonItem = nil self.tabBarController?.navigationItem.setHidesBackButton(false, animated: true) self.projectService.requestAllProjects { (response) in self.projects = self.projectService.loadProjects(response) as! [Project] //println(self.projects.count) dispatch_async(dispatch_get_main_queue()) { self.tableView.reloadData() } } self.userService.requestAllUsers { (response) in self.users = self.userService.loadUsers(response) as! [User] //println(self.users.count) dispatch_async(dispatch_get_main_queue()) { self.tableView.reloadData() } } } 

而这个叫做里面

  override func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell { ... self.projectCell = tableView.dequeueReusableCellWithIdentifier("PickerCell", forIndexPath: indexPath) as! PickerCell let pickerController = MyPickerViewController(pickerData: self.projectService.getArrayOfNames(self.projects)) self.projectCell.configurePickerCell("Progetto", pickerDelegate: pickerController, enabled: true, defaultValueIndex: 0) return self.projectCell ... } 

问题是我得到了标题中的错误，我不知道它是什么意思。 self.projects是从数据库中检索的一个Project对象数组

 NSURLSession.sharedSession().dataTaskWithURL() 

它正确填充，所以我不知道我犯了什么错误。 你能帮忙吗？

更新非常感谢@NickCatib，这是我的工作代码。 注意：Picker视图委托不需要进一步的类。 我刚刚在自定义单元格内实现它：

 import Foundation import UIKit class PickerCell: UITableViewCell, UIPickerViewDataSource,UIPickerViewDelegate { @IBOutlet weak var label : UILabel! @IBOutlet weak var pickerView : UIPickerView! var pickerData:[String]! func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int { return 1 } func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int { return pickerData.count } func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String! { return pickerData[row] } func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) { println(self.pickerData[row]) } func configurePickerCell(labelText:String, enabled:Bool, defaultValueIndex:Int) { self.label.text = labelText var labelFrame:CGRect = self.label.frame labelFrame.size.height = Settings.labelHeight self.label.frame = labelFrame self.pickerView.delegate = self self.pickerView.dataSource = self if (enabled) { self.pickerView.userInteractionEnabled = true } else { self.pickerView.userInteractionEnabled = false self.pickerView.selectRow(defaultValueIndex, inComponent: 0, animated: true) } } } 

Answer 1

那么我会在tableView控制器或单元格本身设置select器视图的委托。 基本上我认为处理UIPicker这些变化的最好方法就是马上，所以尝试在单元或UITableViewController实现delegate 。 既然有机会有多个选手，我会在这个特定的情况下在单元格内处理它们。