在获取聊天logging的同时，我没有从Openfire获取两个用户历史logging
我从openfire中通过在明火中安装开放式火狐插件来获取历史logging，并尝试使用此代码。
let iq1 = DDXMLElement(name: "iq") iq1.addAttribute(withName: "type", stringValue: "get") iq1.addAttribute(withName: "id", stringValue: "0") let retrieve = DDXMLElement(name: "retrieve", xmlns: "urn:xmpp:archive") retrieve?.addAttribute(withName: "with", stringValue: "raman@ip-172-31-53-77.ec2.internal") let set = DDXMLElement(name: "set", xmlns: "http://jabber.org/protocol/rsm") let max = DDXMLElement(name: "max", stringValue: "50") iq1.addChild(retrieve!) retrieve?.addChild(set!) set?.addChild(max) stream?.send(iq1 ) 现在我没有从双方获得历史。 这是我得到的结果。
<iq xmlns="jabber:client" type="result" id="0" to="bentick@ip-172-31-53-77.ec2.internal/5qsinh1syg"> <chat xmlns="urn:xmpp:archive" with="raman@ip-172-31-53-77.ec2.internal" start="2017-02-07T06:28:33.691Z"> <from secs="0"> <body>hello</body> </from> <from secs="405"> <body>hiii</body> </from> <from secs="580"> <body>Hey</body> </from> <from secs="599"> <body>HooooE</body> </from> <from secs="628"> <body>hOo</body> </from> <from secs="907"> <body>Raman here</body> </from> <from secs="931"> <body>Raman here ONE</body> </from> <from secs="1273"> <body>Raman here</body> </from> <from secs="1558"> <body> Raman from SPark </body> </from> <from secs="1571"> <body> Raman from SPark One</body> </from> <from secs="1782"> <body>Raman from SPark </body> </from> <from secs="2651"> <body>Raman FiVE</body> </from> <from secs="2810"> <body>Raman Three</body> </from> <from secs="2810"> <body>Raman FOur</body> </from> <from secs="3534"> <body>RAMAN SIX</body> </from> <from secs="4105"> <body>Raman OKK</body> </from> <from secs="4113"> <body>OKKK l</body> </from> <from secs="4130"> <body>UST</body> </from> <set xmlns="http://jabber.org/protocol/rsm"> <first index="0">0</first> <last>17</last> <count>18</count> </set> </chat> </iq>
这是RAMAN的所有信息，而不是BENTICk，因为这两个用户在获得历史logging时参与聊天，我只收到RAMAN的消息。 不BENTICk如何从双方用户获得历史。
请帮忙。
我已经通过发送给定的iq来实现相同的消息，我得到了正确的结果。
let iQ = DDXMLElement.element(withName: "iq") as! DDXMLElement iQ.addAttribute(withName: "type", stringValue: "get") iQ.addAttribute(withName: "id", stringValue: (xmppHandler.xmppStream?.generateUUID())!) let retrieve = DDXMLElement(name: "retrieve", xmlns: "urn:xmpp:archive") retrieve?.addAttribute(withName: "with", stringValue: "\(JID!)@\(Utility.hostname)") let set = DDXMLElement.element(withName: "set") as! DDXMLElement set.addAttribute(withName: "xmlns", stringValue: "http://jabber.org/protocol/rsm") let max = DDXMLElement.element(withName: "max") as! DDXMLElement max.stringValue = "10" max.addAttribute(withName:"xmlns", stringValue: "http://jabber.org/protocol/rsm") iQ.addChild(retrieve!) retrieve?.addChild(set) set.addChild(max as DDXMLNode) xmppHandler.xmppStream?.send(iQ) <iq type="get" id="7705EEC5-3385-42D4-B748-B39C204ADB90"><retrieve xmlns="urn:xmpp:archive" with="0544008296@192.168.2.181"><set xmlns="http://jabber.org/protocol/rsm"><max xmlns="http://jabber.org/protocol/rsm">10</max></set></retrieve></iq>
响应
<iq xmlns="jabber:client" type="result" id="7705EEC5-3385-42D4-B748-B39C204ADB90" to="0509503847@192.168.2.181/Smack"> <chat xmlns="urn:xmpp:archive" with="0544008296@192.168.2.181" start="2017-02-28T09:55:27.068Z"> <from secs="0" jid="0544008296@192.168.2.181"> <body>Hiii rajeev</body> </from> <to secs="52"> <body>Hi How r u</body> </to> <from secs="15" jid="0544008296@192.168.2.181"><body>I am good</body></from> <to secs="8"><body>What abt u</body></to> <to secs="169"><body>Hello testing chat</body></to> <from secs="10" jid="0544008296@192.168.2.181"><body>Good</body></from> <from secs="5" jid="0544008296@192.168.2.181"><body>Continue </body></from> <to secs="834"><body>Ok </body></to> <to secs="8"><body>Nice chat </body></to> <from secs="232" jid="0544008296@192.168.2.181"><body>Heelo</body></from> <set xmlns="http://jabber.org/protocol/rsm"><first index="0">0</first> <last>9</last><count>574</count></set></chat></iq>