iOS 7中的UIPickerView按钮选择器问题

仅在iOS 7上有一个奇怪的UIPickerView问题

我有一个包含3行的UIPickerView。 每行都有一个按钮，其选择器已定义，但它从不响应按钮点击。

这是我的代码。

- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view { NSLog(@"row %d", row); if(view == nil) { view = [[[UIView alloc] init] autorelease]; } [view setFrame:CGRectMake(0, 0, 320, 44)]; UIButton *manageButton = (UIButton *)[view viewWithTag:TAG_MANAGE + row]; UILabel *descTypeLabel = (UILabel *) [view viewWithTag:TAG_DESCTYPE_LABEL + row]; if(manageButton == nil && row != 0) { CGRect frame = CGRectMake(210, 7, 90, 30); manageButton = [UIButton buttonWithType:UIButtonTypeCustom]; manageButton.frame = frame; [manageButton setTitle:@"Manage" forState:UIControlStateNormal]; [manageButton setTitleColor:[UIColor whiteColor] forState:UIControlStateNormal]; [manageButton setBackgroundImage:[[UIImage imageNamed:@"blackButton.png"] resizableImageWithCapInsets:UIEdgeInsetsMake(8, 8, 8, 8)] forState:UIControlStateNormal]; manageButton.tag = TAG_MANAGE + row; [view addSubview:manageButton]; } if(descTypeLabel == Nil) { descTypeLabel = [[UILabel alloc] initWithFrame:CGRectMake(20, 0, 190, 44)]; descTypeLabel.backgroundColor = [UIColor clearColor]; descTypeLabel.tag = TAG_DESCTYPE_LABEL + row; [descTypeLabel setText:[descTypes objectAtIndex:row]]; [view addSubview:descTypeLabel]; [descTypeLabel release]; } //[manageButton addTarget:self action:@selector(managePressed:) forControlEvents:UIControlEventTouchUpInside]; [manageButton addTarget:self action:@selector(manageButtonPressed:) forControlEvents:UIControlEventTouchUpInside]; return view; } -(void) manageButtonPressed : (UIButton *) sender { //Not Called } 

Answer 1

你需要使用

 - (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component 

而是在iOS 7中，并在其中进行所需的工作。

Answer 2

您不能在选择器视图单元格上使用按钮。 我使用了工具栏并在其上添加了一个条形按钮项。 这样

 - (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component 

您将获得行号并使用它来执行所需的function。