如何在Objective C中实现laravel函数Crypt :: encrypt（）？

我需要实现Crypt :: ecrypt（’123456’）; 从laravel到Objective C iOS 。 所以首先我将用于加密的laravel方法扩展为纯php：

public function enc($text,$key) { $key = (string)base64_decode($key); $iv = random_bytes(16); $value = \openssl_encrypt(serialize($text), 'AES-256-CBC', $key, 0, $iv); $bIv = base64_encode($iv); $mac = hash_hmac('sha256', $bIv.$value, $key); $c_arr = ['iv'=>$bIv,'value'=>$value,'mac'=>$mac]; $json = json_encode($c_arr); $crypted = base64_encode($json); return $crypted; } 

https://github.com/reza-khalafi/LaravelCrypt/blob/master/laravelEncrypt.php

然后逐步将此代码的每一行转换为目标c。 看我的目标c代码：

 #import  #import  // First convert Base64 strings to data NSString *stringIn = @"123456"; NSString *ser = [NSString stringWithFormat:@"s:%lu:\"%@\";",(unsigned long)stringIn.length,stringIn]; NSData *dataIn = [ser dataUsingEncoding:NSUTF8StringEncoding]; //Make iv uint8_t randomBytes[16]; NSMutableString *ivStr; int result = SecRandomCopyBytes(kSecRandomDefault, 16, randomBytes); if(result == 0) { ivStr = [[NSMutableString alloc] initWithCapacity:16]; for(NSInteger index = 0; index < 8; index++) { [ivStr appendFormat: @"%02x", randomBytes[index]]; } NSLog(@"uuidStringReplacement is %@", ivStr); } else { NSLog(@"SecRandomCopyBytes failed for some reason"); } NSData *iv = [[NSData alloc] initWithBase64EncodedString:ivStr options:0]; //Iv base 64 NSString *bIV = [[ivStr dataUsingEncoding:NSUTF8StringEncoding] base64EncodedStringWithOptions:0]; //Key NSString *key = @"9OsNt7h7vjhvOwzXLfdQQYcHxYTua1Fk"; NSData *decodedKeyData = [[NSData alloc] initWithBase64EncodedString:key options:0]; NSString *keyStr = [[NSString alloc] initWithData:decodedKeyData encoding:NSISOLatin1StringEncoding]; //Encryption size_t encryptBytes = 0; NSMutableData *encrypted = [NSMutableData dataWithLength:ser.length + kCCBlockSizeAES128]; CCCrypt( kCCEncrypt, kCCAlgorithmAES128, kCCOptionPKCS7Padding, //CBC is the default mode decodedKeyData.bytes, kCCKeySizeAES128, iv.bytes, dataIn.bytes, dataIn.length, encrypted.mutableBytes, encrypted.length, &encryptBytes ); encrypted.length = encryptBytes; NSLog(@"encrypted hex: %@", encrypted); NSString *encStr = [encrypted base64EncodedStringWithOptions:0]; NSLog(@"encrypted Base64: %@", encStr); //Combine two string NSString *mixStr = [NSString stringWithFormat:@"%@%@",bIV,encStr]; //cHMAC const char *cKey = [keyStr cStringUsingEncoding:NSISOLatin1StringEncoding]; const char *cData = [mixStr cStringUsingEncoding:NSASCIIStringEncoding]; unsigned char cHMAC[CC_SHA256_DIGEST_LENGTH]; CCHmac(kCCHmacAlgSHA256, cKey, strlen(cKey), cData, strlen(cData), cHMAC); NSMutableString *mac = [NSMutableString string]; for (int i=0; i<sizeof cHMAC; i++){ [mac appendFormat:@"%02hhx", cHMAC[i]]; } //Make dictionary NSDictionary *dic = @{@"iv":bIV,@"value":encStr,@"mac":mac}; //Json NSError * err; NSData * jsonData = [NSJSONSerialization dataWithJSONObject:dic options:0 error:&err]; NSString * myString = [[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding]; //Result NSString *lastEnc = [[myString dataUsingEncoding:NSUTF8StringEncoding] base64EncodedStringWithOptions:0]; NSLog(@"%@ %lu",lastEnc,(unsigned long)lastEnc.length); 

代码结果包含192或188个字符串的字符串，这没关系。 但在目的地使用此代码时，响应显示错误：

 Could not decrypt the data. 

我更改了一些代码，并测试了这些方法。 所有的function都是正确的，但我认为CCCrypt与openssl_encrypt不匹配。 因为当我从php获得openssl_encrypt的结果并设置它而不是encStr时 ，总结果正常。

谢谢

Answer 1

  $value = \openssl_encrypt(serialize($text), 'AES-256-CBC', $key, 0, $iv); 

serialize函数 – 它看起来像特定于PHP，它与非ASCII编码不正常。 如果用base64_encode替换它怎么办？ 当然，您也需要修改解密代码。

Answer 2

解决了 ：
最后我们经过太多时间研究Laravel加密，决定自己创建。 LaraCrypt解决了这个问题。 尝试这个：

 pod 'LaraCrypt' 

使用Swift语言的Laravel加密

成功的。